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 The Sun Now  Calculating Focal Length from Plate Scale
Submitted: Tuesday, 10th April 2007 by Anthony Wesley

Something that comes up frequently in planetary imaging is the question of determining the effective focal length of the telescope. This is a non trivial exercise as there is normally at least one barlow element in the optical train, and the actual amount of magnification provided will depend on the specific optical setup - most barlows will either increase or decrease from their nominal power as the camera is moved closer or further away from the top optical element.

For example, the TeleVue 5x powermate will increase its power by 1x for every 35mm of extra distance introduced between the top of the powermate barrel and the focal plane of the camera. (reference: Televue Powermates).

In practice, this and other variables in the optical system make it very difficult to accurately calculate the effective focal length of the instrument.

The solution is to work backwards from a captured image and calculate the focal length directly. All you need to know the pixel size of your camera (in microns) and then use the following formula:

F = 206.265 x P x U

---------------
O
• P is the size of the object in pixels as captured
• U is the pixel size of the camera in microns
• O is the true size of the object in arc-seconds
• F will be the focal length as calculated from this formula, in mm.

### Worked Example

Here is an image of Jupiter taken on the 27th of March 2007, lets work out the focal length of my telescope using it as a practical example.   Click to EnlargeJupiter, by Anthony Wesley • The camera I used was a Dragonfly Express which has 7.4 micron pixels, i.e. U = 7.4
• Jupiter was 39.7 arcseconds in diameter, i.e. O = 39.7 (measured across the equator )
• On the image above I measure the diameter across the equator to be approximately 342 pixels, i.e. P = 342

So my effective focal length was:

```F = 206.265 x 342 x 7.4
-------------------
39.7```

= 13,149mm

The diameter of my primary mirror is 331mm, so this means I was using a focal ratio of 13149/331 = f/39.7.

So there you go, no more head scratching required to work out what focal length was in use in your planetary images. Advertisement  Advertisement  Advertisement  Advertisement  Advertisement  Advertisement 