Quote:
Originally Posted by malclocke
Ahh ... I wasn't aware that cuberoot(x) was the same as x^1/3, I was a lot closer to solving it than I thought. There may yet be hope for me!
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That's right Malc, this holds for all roots; taking the root of something is the same as raising it to the inverse power, eg. Squareroot(x) = x^1/2