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Old 10-12-2011, 03:12 PM
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shelltree (Shelley)
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Join Date: Jul 2009
Location: Brisbane, Australia
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Calculating the distance between a "5 cent coin sized" sun to Proxima Centauri

After reading this http://www.wired.com/wiredscience/20...universe-size/ posted by Jon in a previous topic in this section, I became interested in trying to calculate the distance between the Sun and Proxima Centauri, using a 5 cent piece with a 19.41mm width as a scale.

Now I know NOTHING about Maths, I failed high school maths so it all gets a bit confusing sometimes but I was determined to see if I could do it anyway.

I will put my very rough calculations below. If anyone could tell me how completely wrong I am, that would be very helpful I think I have gone completely off the track with how I tried to calculate it and if someone could please help me solve this, I would be forever greatful

40000000000000 km to Proxima Centauri

5 cent piece = 19.41mm

1km = 1000000mm so 40000000000000km = 40000000000000000000mm?

1,391,980 km = width of sun

Width of sun in millimetres = 13919800000000mm

So, 19.41mm = 13919800000000mm

40000000000000000000 divided by 13919800000000 = 2873604.5058118651130044971910516

19.41 x 2873604.5058118651130044971910516 = 55776663.457808301843417290478312

55776663.457808301843417290478312mm = 55.7766634578km

55.7766634578 - 0.0000001941 = 55.7766632637km

So, the distance between the Sun and Proxima Centauri, using the scale of a 5 cent piece as the Sun (19.41mm) = 55.7766634578km

I'm crazy, I know And have got this all completely wrong but would appreciate some help
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