Quote:
Originally Posted by renormalised
m-M=5logD-5, with m=apparent magnitude, M=absolute magnitude and D=distance to object (Star) (log being base 10)
However, to get D, you need to manipulate the equation, like this...
D= 10^(m-M+5)/5 (in parsecs)
So, a star with m=8 and M=2.3 would be....
D=10^(8-2.3+5)/5
=10^2.14
=138pc
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Reminding me of my Astronomy 101 course
. I am also learning Derivatives and anti-derivatives at the moment. Can be perplexing but I have an excellent Math teacher.
I expect my next year will be intense
I Remember M is at 10MPc
