Quote:
Originally Posted by bojan
Exactly.
I should have presented the math as follows:
180 * (47/36) * (36/12) = 180 * 47 * 36 /(36*12) = 705
or
180 * 47 * (36/36) /12 =705
This is the same as
180 * 47/12 = 705 because 36/36 =1... so you see the middle gear could in principle have any number of teeth (even only single one.. mathematically this is OK but in reality/practice of course this doesn't make sense).
BTW, your drawing is not correct.
The main worm gear has 180 teeth (as you indicated,) but it is driven by worm (like screw, resulting in 1:180 ratio at this tage) and not by 47-teeth gear as on your drawing.
Perhaps this is also one of the reasons you have been confused.
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I'm beginning to see the light. Does it also make no difference what the diameter of the transfer gear is? As a matter of interest, I just threw a micrometer across them and the 32-tooth was 27.3mm and the 36 tooth was 30.4mm.
Peter