Gravity and The Curvature of Space Question
Here's something I can't get my mind around.
Take a black hole. There is no path from any point within the event horizon to any point outside of the event horizon - no outward path. Space is curved back onto itself and any path for a photon that is within the event horizon leads to the singularity.
So - if I've got this correctly. Get a wire frame to represent the three spatial axes and place it within the event horizon. Now as we we migrate along any of the axes we find ourselves at the singularity.
But we have have an inward direction that allows for material to cross over the event horizon from the outside to the inside. This could possibly (or possibly not) be rephrased as there is a direction - independent from the three spatial dimensions - that allows a vector to be constructed that gravitationally binds an object outside of the event horizon and the singularity - and possibly any object that has crossed the event horizon but has not yet reached the singularity.
So in how many "directions" is gravity operating - the three internal (within the event horizon) spatial 3D plus radially outwards (what ever that means) in an external 3D frame of reference - is that effectively six - and how would that effect any test of the inverse square law?
Its a brain teaser for me.
I'm not trying to be provocative - its a genuine Winnie the Pooh type of experience - you know - "I'm a bear of little brain and big words bother me".
If I got a nudge or a clue I'd be happy.
Mark C.
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