Quote:
Originally Posted by OICURMT
This doesn't sound correct to me though, as a standard deviation would actually result in a 68.2% level of confidence... can anyone clarify this?
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That's correct assuming a standard normal curve.
You have that variables of mean and variance to play with to alter those numbers. In reality the variance will be based on the geometric probabilities of the assumed asteroid orbit and size together with estimated stellar position.
It's way over my head!