[Robh (Rob)]

Originally Posted by sjastro

c^2=a^2+b^2
a^2=c^2-b^2
a^2=(c+b)(c-b)

Hence a^2=(b+c) if (c-b)=1.

Regards

Steven

Great to see someone take the time out to derive the condition.
Pythagoras would be pleased!

Regards, Rob.