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The linear image size = angular image size (deg) x effective focal length of telescope / 57.3
eg. Moon = 0.5 deg. Image size on film plane for 8" SCT = 0.5 x 2000 / 57.3 = 17.5mm
eg. Mars = 14.1 arc sec = 0.0039 deg at best this opposition. Image size on film plane for 8" SCT = 0.0039 x 2000 / 57.3 = 0.14mm (Small!)
I am not an imager and am not familiar with the Meade DSI II and so am not sure of its sensor size or the size of each pixel. However, I would think you need a little more focal length to capture Mars effectively. This can be achieved with a 2x or 3x Barlow or 2x, 2.5x, 4x or 5x Powermate.
Look at what equipment others are using in the Images\Solar System part of the forum to get some ideas. No harm in trying with what you have though.
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