Quote:
Originally Posted by Shnoz
The equation is as follows.
't = (t - v/csquared)/(square root of1 - vsquared/csquared)
't - observer's time
t - moving object's time
v - velocity
c - speed of light
So what exactly is the answer to this equation? What's the time difference between and observer's time and a photon's time?
Or I could have simply made a mistake in my understanding. Either way, I need answers!  |
I'm not sure about this equation Sophie. It doesn't look like the time dilation formula I'm used to.
See:
http://en.wikipedia.org/wiki/Time_dilation
But no matter... The faster something travels, the more it slows down. The limit of the formula as v approaches c is 0 (even though technically it is undefined, the limit provides some guidance on what to expect). So as Bert already replied, the photon doesn't experience time... it "experiences" going from start to finish instantly.
Al.