Quote:
Originally Posted by skwinty
A question here on this statement.
Given the extreme pressure and temperature experienced by the mass in this circumstance, I would have thought that the atoms and their associated particles would be completely disassociated into some kind of particle soup.
Where would you find order in that? Is enthalpy the correct term here?
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They are, and you're correct in stating that. However, the order comes in the values of the system as a whole. It has a defined mass, the gravitational pull is of a certain intensity (even if it does approach infinity), it has a specific density, size etc etc. If it was in a highly disordered state, it would have none of those.
Just had a thought.....given that at absolute zero, entropy reaches its minimum state and everything is in total disorder, by rights a black hole would cease to exist. It would instantly radiate away all the energy it had (gravitational, angular momentum etc etc) because its surroundings would be devoid of everything...light, heat etc etc. Since it would have to obey the 1st law (i.e. "hot" flows to "cold"), it would lose its order completely by radiating it away. However, it would only be a momentary thing....the moment it's surroundings reached maximum disorder, the hole would flash vapourise into nothingness and instantly raise its surrounding to a temp' of trillions of degrees. So, it'd be going from the sublime to the ridiculous, so to speak.
But all that is assuming the hole doesn't lose order as the temp decreases. It would, however you have the problem of the singularity and the damn cold. One is (for sake of argument) an infinitely deep gravitational well. The other is just a precisely defined temp at which everything grinds to a halt. If the gravitational well is infinitely deep, then it must possess infinite energy. It wouldn't matter how cold it got, how do you "freeze" infinite energy??!!!! It would be infinitely hot right at the zero point of the singularity.
Figure that one out.