FOV formula for Image at Prime Focus
Would like to confirm if the following formula is correct to find out your FOV at prime focus when imaging targets
Formula
Width of camera chip in mm x 3460 / Telescope focal length in mm
Example: My 8” f5 newt with a Canon 600 D at prime focus
So width 22.3mm x 3460 / 1000mm = 77.2 arc minutes
and height 14.9mm x 3460 / 1000mm = 51.5 arc minutes
Therefore image FOV would be 77.2 arc minutes wide and 51.5 arc minutes high
Please advise if the above is correct?
Thanks in advance
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