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Just to clarify Joes comment
The depth only equals the circle dia for a 60deg groove.
Basically, if the cylinder is drawn as described, the centre of the cylinder to the bottom of the groove is also the depth reqd.
If you draw a line from the centre of the cylinder to where the cylinder contacts one side of the groove, you get a line that is at 90deg to the side of the groove.
This makes a right angle triangle from centre of cylinder, base of groove and contact point.
In this scenario, depth is the hypotenuse, cylinder radius is the opposite ( ie 1mm ) and the angle is 1/2 the groove angle ( ie 30deg )
sooo by std definitions, depth * sin(30) = 1
and as sin(30) = 0.5, depth = 2
Ff you use any other angle, you need to adjust the sin(X) part.
Andrew
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