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Old 14-02-2015, 01:33 AM
ericwbenson (Eric)
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ericwbenson is offline
 
Join Date: Sep 2009
Location: Adelaide, Australia
Posts: 209
Quote:
Originally Posted by gaston View Post
FWHM ~ =0.25*lambda/r0 (lambda in nm and r0 in cm, FWHM in arc second).

Assuming an average seeing with a r0 = 10cm at 550nm the FWHM seeing is about 1.4”, a bad seeing with r0=5cm gives about 2.8”.

The above should read :
FWHM ~ =0.25*lambda/r0 (lambda in nm and r0 in mm, FWHM in arc second).

Regards,
EB
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