Quote:
Originally Posted by gaston
FWHM ~ =0.25*lambda/r0 (lambda in nm and r0 in cm, FWHM in arc second).
Assuming an average seeing with a r0 = 10cm at 550nm the FWHM seeing is about 1.4”, a bad seeing with r0=5cm gives about 2.8”.
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The above should read :
FWHM ~ =0.25*lambda/r0 (lambda in nm and r0 in
mm, FWHM in arc second).
Regards,
EB