Quote:
Originally Posted by Nortilus
ok
ʃ{e^2x/5+e^2x}dx
so the (intergral of e to the power of 2x over 5 + e to the power of 2x) dx
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There are two possible interpretations of your problem, depending on where the implied parentheses go:
Do you mean:
ʃ{(e^(2x))/5+e^(2x)}dx
or:
ʃ{e^(2x/5)+e^(2x)}dx
See attached - hope this helps!