Looking for Maths Genius for Uni help

[Nortilus]

Hi,
I really need some help with some math I'm having trouble with. PM me if you can and I'll send you an email address or facebook friends request. Getting desperate.
Thanks

[LewisM]

Post it here - you'll be surprised.

[Nortilus]

ok

ʃ{e^2x/5+e^2x}dx

so the (intergral of e to the power of 2x over 5 + e to the power of 2x) dx

[LewisM]

GRRRR integration and log... not my area sorry!

[Nortilus]

this is spose to be math B equivilent and know one knows it.

[julianh72]

There are two possible interpretations of your problem, depending on where the implied parentheses go:

Do you mean:

ʃ{(e^(2x))/5+e^(2x)}dx

or:

ʃ{e^(2x/5)+e^(2x)}dx

See attached - hope this helps!

[Nortilus]

written like this (see attached)

[Nortilus]

sorry that its sideways. straight from phone

[julianh72]

There are THREE (or more!) possible interpretations of your problem, depending on where the implied parentheses go:

ʃ{(e^(2x))/(5+e^(2x))}dx = ln(e(2x) + 5) / 2

See attached!

[mithrandir]

Julian you left out a "^" on the RHS.
Going by Josh's handwritten version that's what he meant. If you go to the LaTeX test site http://arachnoid.com/latex/ and paste in:

\int{\frac{e^{2x}}{{5+e^{2x}}}dx} \rightarrow \frac{\ln(5+e^{2x})}{2}

you'll get Julian's image - or something equivalent (commutative law).

[GeoffW1]

Good stuff Julian. Takes me back to those late nights studying

Cheers