View Single Post
  #10  
Old 20-01-2013, 11:54 PM
mithrandir's Avatar
mithrandir (Andrew)
Registered User

mithrandir is offline
 
Join Date: Jan 2009
Location: Glenhaven
Posts: 4,161
Quote:
Originally Posted by OzEclipse View Post
Andrew,
Sorry about that :
It is:-
max exposure time(s) = [14*N*P] / [FL*cos(d)]

I've edited the original post to reflect this.
It seemed to make more sense that way than the other so I thought I check it.

Quote:
The cos(d) term is 1 for a declination of 0 so you can leave it out all together if you want to calculate for stars on the celestial equator.
To make use of that you need to know the image center and FOV to work out "d".
eg APS-C long axis 23.3mm. At 11mm -> 93° FOV so pointed at dec -45 with that axis aligned n/s some stars are on the equator.
Reply With Quote