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Doing a quick bit of math
The onscreen image @ 25 % has a width of 205 mm halo diameter is 33 mm
Chip is 3032 pixels wide and each pixel 7.8 micro
33/205= .16097
3032 x .16097 x 7.8 = 3.80687 mm
F ratio is 7
F ratio times diameter /2 is
7 x 3.80687 /2 = 13.324 mm
Therefore it has to be the ir filter on the camera as thats got to be the distance...... Lovely bit of maths you've given me there Eric. Looks like the problems identified, next question is there a better quality filter that will not reflect so much light or alternatively moving the filter further away will reduce it's effect by distance squared by spreading it further, I prefer a new filter first
Anyone know of a filter solution ????
Thanks again Eric
Clive
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