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Just to make sure though - the noise being the square root of the signal applies only to light, right?
The Dark Current Noise is squared in the equation too because thermal noise is still light, even if it's not visible light, so it accumulates in the same fashion.
And as Mark mentioned, RMS is already rooted, so it has to be squared first to end up with the correct contribution to the total noise as the terms are added.
Have I got that right?
Markus
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