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Why is noise the square root of signal?
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16-01-2019, 10:22 PM
Stonius
(Markus)
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Join Date: Mar 2015
Location: Melbourne
Posts: 1,495
So does that mean that on a perfectly calibrated frame, the StdDev will always = SQRT(mean)?
I'm trying to see if that holds true with actual data and whether I can use that principle to see how far I am off a perfect calibration if it doesn't.
M
Stonius
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